Question

If length of a conductor and it's area of cross-section is increased twice, how the resistance will change? *​

Answer 1

Answer:

please mark

Explanation:

If the original length of the wire is l and its cross-sectional area is A, then its resistance, R=ρl/A. When the length becomes 2l, cross-sectional area reduces to A/2 because volume of the wire does not change. Changes resistance, R′=ρ(2l)(A/2)=4ρlA=4R