if length of a diagonal of a rhombus is 30 cm and its area is 240 sq cm find its perimeter
Answers
If the length of a diagonal of a rhombus=30cm
Area =240cm^2
Let's take the length of the other diagonal be x
The formula for finding the area of rhombus is 1/2*first diagonal *second diagonal
According to question : The product of 1/2,first diagonal =30 and second diagonal =x gives the result area of the rhombus =240cm^2
So, 1/2*30*x=240
=>1*15*x=240
=>15x=240
=>x=240/15
=>x=16
Since, the second diagonal is 16cm
The half of first diagonal =30/2=15
The half of second diagonal =16/2=8
Since, all sides of the rhombus are equal
So we should use the pythagorean theorom, that is side=root over of(15) ^2 +(8)^2 =root over of 225+64=root over of289=17
Since, all sides of the rhombus are equal
Perimeter =17*4=68cm
Therefore the perimeter is 68cm
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