Question

If length of a rectangle exceeds its breadth by 5m if the perimeter of the rectangle is 90m then the length of the rectangle is​

Answer 1

Let, the length of rectangle be x.

Then, breadth=(x+5)m.

perimeter of rectangle=90m.

A/Q,

perimeter of rectangle=2(l+b).

90=2(x+x+5)

90=2(2x+5)

90=4x+10

90-10=4x

80=4x

x=80/4

x=20

Hence, length=20m

breadth=(20+5)=25m

Answer 2

Answer:

Let the length be x and breath be y

So x-y = 5

x = 5+ y

Perimeter of rectangle 2(l+b)=90

2(5+y +y) = 90

4y+ 10 =90

4y =80

y = 20

x = 25

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