Math, asked by jskarrey3476, 9 months ago

If length of a rectangle is decreased by 6 cm we get a square and the area of square formed is 252 cm2 less than the area of square formed when breadth of the original rectangle is increased by 6 cm. Find the perimeter of the rectangle.

A) 66 cm B) 88 cm C) 80 cm D) 72 cm

Answers

Answered by Anonymous
2

Answer:

If length of a rectangle is decreased by 6 cm we get a square and the area of square formed is 252 cm2 less than the area of square formed when breadth of the original rectangle is increased by 6 cm. Find the perimeter of the rectangle.

A) 66 cm

B) 88 cm C) 80 cm D) 72 cm

Step-by-step explanation:

A) 66 cm

Answered by kumaradi
0

Answer:

Answer- 84 cm

Let length be L and breadth be B

When (L-6) then square (S1). So, side of S1 is (L-6)

Area (S1) = (L-6)^2

Thus, B is also (L-6) => L = B + 6

Now, also Question says Area (S1) = Area (S2) - 252

Area (S2) = (B +6)^2 = L^2

So, L^2-(L-6)^2 = 252

L = 24 and B = 18

Then, Perimeter = 2(24+18) = 2×42 = 84 cm

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