Question

If length of a rectangular field in 22m and breadth is 20m Find the perimeter and area of rectangle​

Answer 1

Answer:

Step-by-step explanation:

   -----------------------------Here is you Answer Mate ---------------------------------

According to the question,

Given,

Length = 22 meters

Breadth = 20 meters

So therefore,

Perimeter of Rectangular Field = 2 * (Length + Breadth)

=> 2 * (22 + 20)

=> 2 * 42

=> 84 cm

Area of Rectangular Field = Length * Breadth

=> 22 * 20

=> 440 $cm^{2}$

   -----------------------------Hope this helps you Mate------------------------------------

Answer 2

${\tt{\red{\underline{\underline{\huge{Answer:= \: }}}}}}$

$\boxed{ \sf \pink{ Perimeter \: = \: 84cm }}$

$\boxed{ \sf \pink{ Area \: = \: 440cm }}$

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$\LARGE{\bf{\underline{\underline\color{blue}{GIVEN:-}}}}$

$\sf\green{Length\:of\:rectangle \: =\: 22m}$

$\sf\green{Breadth\:of\:rectangle \: =\:20m }$

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$\LARGE{\bf{\underline{\underline\color{purple}{Solution:-}}}}$

Perimeter =

$\boxed{ \sf \blue{We \: will \: use \: the \: Formula \: to \: find \: perimeter }}$

$\boxed{ \sf \red{Formula }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:2 \: ( \: Length \: + \: Breadth \: ) }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 2\: ( \: 22 \: + \: 20 \: ) \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 2\: ( \: 42 \: ) \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Perimeter \: = \: 84cm }} }\\ \\\end{gathered}\end{gathered}$

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Area =

$\boxed{ \sf \blue{We \: will \: use \: the \: Formula \: to \: find \: Area }}$

$\boxed{ \sf \red{Formula }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Length \: × \: Breadth \: }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: 22 \: × \: 20 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: 440cm }} }\\ \\\end{gathered}\end{gathered}$

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