Question

If length of a resistance wire become half and cross section area becomes twice ,then find the relation between old resistance and new resistance.​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

$R=\rho\frac{l}{A}$ ------------(1)

Length of resistance of a wire is l/2.

The cross-sectional area becomes 2A.

Thus, the new equation becomes:

Thus, $R=\rho\frac{l}{2\times2A}$

$R_{1} =\frac{1}{4} (\rho\frac{l}{A})$ -----------(2)

Substitute (1) in (2)

$R_{1} =\frac{1}{4} (R)$

Thus, the new resistance is 1/4th of the old resistance.

HOPE THIS HELPS :D