If length of a rod l is (4.0±0.1)m and it's mass M is (5.0±0.1) kg, then the maximum percentage error in measurement of moment of inertia is ( moment of inertia is directly proportional to ML2)
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Let us take the length as 'a' and relative error in a be Δa, and Mass as 'b' and Relative error in Mass be Δb.
Using the formula of the Total error in percentage,
Total Percentage error = Δa/a × 100 + Δb/b × 100
∴ % Error = 0.1/4 × 100 + 0.1/5 × 100
∴ % Error = 2.5 + 2
∴ % Error = 3.5 %
Hope it helps.
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