if length of a room is 5 metre Breadth is 4 and height is 3 then find the longest word which can be adjust in the room without bend of the road
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Length, breadth and height of a room are 5 m, 4 m and 3 m.Area of four walls of the room = 2h(l + b) = 2 × 3 (5 + 4) = 6(9) = 54 sq mArea of the ceiling ...
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Area to be white washing=2h(l+b)+lb
=2×4(5+3.5)+(5×3.5)
=68+17.5=85.5㎡
Total cost of white washing=Rs. (85.5×15)=Rs. 1282.5
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