if length of diagonal of rhombus is 30 cm and its area is 240 square centimetre find its perimeter
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area of rhombus=1/2*diagonal 1*2diagonal
area=1/2*30*2diagonal
240=15*2 diagonal
16=2 diagonal
now perimeter=4*side
for perimeter we apply Pythagoras theorem as we know to sides of rhombus as diagonal make 90° where they meet.
so it's right angle triangle.
h^2=15^2+8^2
h=17cm {aprox.}
now perimeter =4*17
perimeter=68
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