If length of minute hand of a clock is 14 cm, the area swept by the minute hand in one minute is
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length of minute hand r= 14cm
area swept by the minutes hand in 60 min
= πr^2 = 22( 14)^2/ 7 = 616cm^2
angle made to cover area of watch in 60minutes = 360°
in 1 min = 360 ÷ 60 = 6°
area swept by the minutes' hand in 1min
= 6° × πr^2/ 360°
= 1 × 616/ 60 = 10.27 cm^2
area swept by the minutes hand in 60 min
= πr^2 = 22( 14)^2/ 7 = 616cm^2
angle made to cover area of watch in 60minutes = 360°
in 1 min = 360 ÷ 60 = 6°
area swept by the minutes' hand in 1min
= 6° × πr^2/ 360°
= 1 × 616/ 60 = 10.27 cm^2
Answered by
6
length of minute hand r= 14cm
area swept by the minutes hand in 60 min= πr^2
= 22( 14)^2/ 7 = 616cm^2
60 min = 616cm^2
1min = 616 ÷ 60 = 10 4/15cm^2
area swept by the minutes hand in 60 min= πr^2
= 22( 14)^2/ 7 = 616cm^2
60 min = 616cm^2
1min = 616 ÷ 60 = 10 4/15cm^2
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