Question

If length of rectangle is 20m and area of the rectangle is 400m; find the breadth.
Please give solution step by step​

Answer 1

$\red\bigstar{Solution}$

Given :-

• .Length of rectangle is 20m
• Area of rectangle is 400m²

To find :-

• Breadth of rectangle

Formula to know:-

$\ \: area \: of \: rectangle \: = length \times breadth$

Solution:-

$\\ pluging \: values$

$\: \: 400m {}^{2} = 20m \times breadth$

$20m \times 20m \: = 20m \times breadth$

$breadth = 20m$

$\: \: \: \: \: so \: breadth \: of \: rectangle \: i \: 20m$

Know more :-

$\: \: \: Perimeter of square = 4a$

$\: \: \:Perimeter of rectangle = 2(l+b)$

$\: \: \:Perimeter of rhombus = 4a$

$\: \: \:Perimeter \:of\: isosceles triangle = 2a+b$

$\: \:\:Perimeter\: of\: equilateral triangle = 3a$

$\: \: \:Perimeter \:of\: parallelogram = 2 (a+b)$

$\: \: \: Area \:of \:rectangle = l b$

$\: \: \: Area \:of \:square = a^2$

$\: \: \: Area \: of \: Rhombus = 1/2d_1d_2$

Answer 2

Answer:

Breadth = 20 m

Step-by-step explanation:

Area of the rectangle = L × B

Area = 400 m

Length = 20 m

Breadth = ?

$\sf Breadth = \frac{Area \: of \: the \: rectangle}{Length \: of \: the \: rectangle}$

$\sf Breadth = \frac{400 \: m}{20 \: m} = 20 \: m$