Question

if length of rectengular field is twice that of its width.find the perimeter of the field of its area 1152 m?​

Answer 1

Correct Question

The length of a rectangular field is twice its breadth and the area of the field is 1152 m². Find the perimeter of the field.

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Given

Breadth = x

Length = 2x

Area of Rectangle = 1152 m²

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To Find

Perimeter of rectangular field

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Solution

Breadth = x

Length = 2x

Area of Rectangle = Length × Breadth

Area of Given Rectangular Field = 2x × x = 1152 m²

Now we'll solve this equation to find the length and breadth.

Let's solve your equation step-by-step

$2x \times x = 1152$

Step 1: Simplify both sides of the equation.

⇒ $2x \times x = 1152$

⇒ $2x^{2} = 1152$

Step 2: Divide both sides by 2.

⇒ $\dfrac{2x^{2} }{2} = \dfrac{1152}{2}$

⇒ $x^{2} = 576$

Step 3: Find square root of 576.

⇒ $x^{2} = 576$

⇒ $x=24$

∴ Length = x = 24

∴ Breadth = 2x = 24 × 2 = 48

Perimeter of Rectangle ⇒ 2 (Length × Breadth)

Perimeter of Given Rectangular Field ⇒ 2 (24 + 48)

⇒ 2 (72)

⇒ 144

∴ The perimeter of given rectangular field is 144 m.

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Answer 2

Question

If length of rectengular field is twice that of its width.find the perimeter of the field of its area 1152 m²?

Solution

Area of the rectangular field = 1152m²

Let, it's width be x

it's length be 2x

ATP

$2x \times x = 1152 \\ = ) \: 2 {x}^{2} = 1152 \\ = ) \: {x}^{2} = \frac{1152}{2} \\ = ) \: {x}^{2} = 576 \\ = ) \: x = \sqrt{576} = 24$

Length = (2×24)m = 48m

Width = 24m

Perimeter = 2(l+b)

= 2(48+24)m

= (2×72)m

= 144m

Ans:- The perimeter of the field is 144m.

More Information

Surface area of cuboid = 2(lb+lh+bh)

Surface area of cube = 6 (length of an edge)²

Area of four walls = 2(l+b)h

Lateral surface area of cuboid = 2(l+b)h

Lateral surface area of cube = 4 (length of an edge)²