Question

If length of shadow =20m and of elevation =60m then find height of tower?

Answer 1

by Pythagoras theorem

Hypotenuse=60m
base=20m
perpendicular=?

${20 } ^{2} + b^{2} = {60}^{2}$
$400 + b ^{2} = 3600 \\ b {2} = 3600 - 400 \\ b ^{2} = 3200 \\ b = \sqrt{3200}$
height of tower =✓3200