If length of the conductor of resistance 1 ohm is stretched to thrice of its initial length, then find the new resistance of the conductor.
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Explanation:
9ohm
resistance is directly proportional to square if length (coz area remains constant here)
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9 ohm
The stretching of wire is constant since the volume is constant.
L=Length of the wire
A=area of the wire
R=resistance
R = ρ L A
A1×L1=A2×L2
L2=3L1
A2=A1÷3
R ′ = ρ×3L÷(A/3)
R ′ =9×R
A resistance R wire is stretched until it reaches n times its initial length. The area of cross section goes from A to A times n when the length is extended n times to n times length.
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