Question

If length , width and perimeter of a rectangle are repectively (a+3) cm,(2a-5) cmm and 26 cm then area of rectangle will be

Answer 1

area of square = area of rectangle

area of square = x^2

let length of rectangle be (a) cm and width be (b) cm.

area ofrectangle =a*b

perimeter of rectangle =26 cm

so

2(a+b)=26

a+b=13

if length =12 cm and width =1 cm

so,are of rectangle=12*1=12 cm^2

lif ength =11 cm

and width =2 cm

area of rectangle=11*2 =22 cm ^2

if length =10 cm and width =3 cm

so,are of rectangle=10*3=30 cm^2

if length =9 cm and width =4 cm

so,are of rectangle=9*4=36 cm^2

if length =10 cm and width =3 cm

so,are of rectangle=10*3=30 cm^2

if length =9 cm and width =4 cm

so,are of rectangle=9*4=36 cm^2

if length =8 cm and width =5 cm

so,are of rectangle=40 cm^2

if length =7 cm and width =6 cm

so,are of rectangle=42 cm^2

Area of sqauare can be found be

1^1=1 cm^2

2^2=4 cm^2

3^2=9 cm^2

4^2=16 cm^2

5^2=25 cm^2

6^2=36 cm^2

7^2=49 cm^2

there is one common area=36 cm^2

so,Area of square=area of rectangle=36 cm^2

PLEASE MAKE ME BRAINLIST

Answer 2

Step-by-step explanation:

length of rectangle=a+3

width of rectangle=2a-5

perimeter=26

A/q

perimeter=2(l+b)

26=2(a+3+2a-5)

26=2(3a-2)

26=6a-4

-6a=-4-26

-6a = -30

a= -30/-6(-/-=+)

=5