Question

If θ lies in the 2nd quadrant & tanθ=-5/12,find the value of (2cosθ)÷(1-sinθ)

Answer 1

Answer:

The value of (2cosθ)÷(1-sinθ) = -2

Step-by-step explanation:

tanθ = P/B = -5/12

So, H = 13

Since θ lies in the 2nd quadrant,

sinθ will be positive

sinθ = P/H = 5/13

cosθ will be negative

cosθ = B/H = -12/13

Now,

(2cosθ)÷(1-sinθ)

= (2*(-12/13))÷(1-5/13)

= (-24/13) ÷ ((13-5)/13)

= -24/13 ÷ 12/13

= -24/13 * 13/12

= -2

.

Hope it helps!