Question

If limiting molar conductivity of Ca2+ and Cl– are 119.0 and 76.3 S cm2 mol-1, then the value of limiting molar conductivity of CaCl2 will be
(a) 195.3 S cm2 mol-1
(b) 271.6 S cm2 mol-1
(c) 43.3 S cm2 mol-1
(d) 314.3 S cm2 mol-1.

Answer 1

Therefore option (b) is correct choice.

Given : If limiting molar conductivity of Ca²⁺ and Cl¯ are 119.0 and 76.3 S cm² mol¯¹.

To find : The value of limiting molar conductivity of CaCl₂.

solution : from Kohlrausch's law,

$\Lambda_{CaCl_2}=\Lambda_{Ca^{2+}}+2\Lambda_{Cl^-}$

⇒$\Lambda_{CaCl_2}$ = 119 + 2 × 76.3

= 119 + 152.6

= 271.6 cm²mol¯¹

The limiting molar conductivity of CaCl₂ is 271.6 cm²mol¯¹

Therefore option (b) is correct choice.

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Answer 2

Answer:

▪︎b option is correct.

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