If Limx->1 (x⁴-1)/(x-1)=Limx->k (x³-k³)/(x²-k²), find the value of k
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0
Answer:
k value should be 8
Step-by-step explanation:
I thought it's limix
Answered by
1
Answer:
K=8/3
Step-by-step explanation:
here given lim x tends to 1 x^4-1/x-1=lim x tens to k x^3-k^3/x^2-k^2
here when substitute individual we are getting 0/0
so apply L hospital rule then on differentiating
we get
4x^3=3/2k
k=8/3
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