If limxtends to 2 xn-2n /x-2=80 what is n
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lim x-->2 (x^n - 2n )/ (x-2) = 80
by using L-Hospital rule, the simplest one
lim x-->2 {nx^(n-1)} = 80
n (2)^n-1 = 80 = 5(2)^4 = 5(2)^5-1
so, n=5
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