IF LINE AC AND BD INTERSECT AT POINT O SUCH THATIF LINE AC AND BD INTERSECT AT POINT O SUCH THAT<AOB:<BOC=2:3 FIND <AOD
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<AOB+<BOC=180 DEGREES (STRAIGHT LINE ANGLE)
SUM OF TERMS OF RATIO=2+3=5
<BOC=(3/5)*180=108 DEGREES
<AOD=<BOC (VERTICALLY OPPOSITE ANGLES)
THEREFORE,<AOD=108 DEGREES
SUM OF TERMS OF RATIO=2+3=5
<BOC=(3/5)*180=108 DEGREES
<AOD=<BOC (VERTICALLY OPPOSITE ANGLES)
THEREFORE,<AOD=108 DEGREES
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