if line kx+4y=12 passes through point (1,0) find k
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12
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Answered by
1
substitute values of the point in the equation, we get
k+0=12
therefore k = 12
k+0=12
therefore k = 12
Answered by
0
Firts the 1,0 are substitute the value for x and y then k(1)+4(0)=12
k+0=12
k=12
k+0=12
k=12
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