if line kx+4y=12 passes through point (1,0) find k ?
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Answered by
1
since line passes through (1,0)
therefore it will satisfy the given equation
k×1+4×0=12
k=12
therefore it will satisfy the given equation
k×1+4×0=12
k=12
Answered by
1
If line passes through (1,0),then x=1 and y=0
Now we will put the value of x and y in the equation kx+4y=12
k*1+4*0=12
k+0=12
k=12
Therefore, value of k=12
Now we will put the value of x and y in the equation kx+4y=12
k*1+4*0=12
k+0=12
k=12
Therefore, value of k=12
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