if line PQ and RS intersect at point t such that |_PRT =40° |_RPT =95° and |_TSQ =75° find |_SOQ
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Here is ur answer.
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Hello mate ☺
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Solution:
In ∆PRT, we have
∠PRT+∠RPT+∠RTP=180° (Sum of three angles of a triangle =180°)
⇒40°+95°+∠RTP=180°
⇒∠RTP=180°−40°−95°=45°
∠RTP=∠QTS (Vertically Opposite Angles)
Therefore, ∠QTS is also equal to 45°
In ∆STQ, we have
∠SQT+∠TSQ+∠QTS=180° (Sum of three angles of a triangle =180°)
⇒∠SQT+75°+45°=180°
⇒∠SQT=180°−75°−45°=60°
I hope, this will help you.☺
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