Question

if line represented by equation ax+4y+5=0 and 6x +12y+c=0 are coincident. find the values of a, c​

Answer 1

Answer:

The coincident lines are given as,

3x+4y+2=0

And

9x+12y+k=0

Comparing the equations with the general equations

a

1

x+b

1

y+c

1

=0

a

2

x+b

2

y+c

2

=0

Then,

a

1

=3,b

1

=4,c

1

=2,a

2

=9,b

2

=12,c

2

=k

Since, the lines are coincident, then,

a

2

a

1

=

b

2

b

1

=

c

2

c

1

9

3

=

12

4

=

k

2

3

1

=

3

1

=

k

2

3

1

=

k

2

k=6

Answer 2

Answer:

$ax + 4y + 5 = 6x + 12y + c$

$ax + c = 12y - 4y + 6 - 5$