if line segments DA,CB and OM perpendicular on segment AB , Where O is the intersecting points for line segment AC and DB.if OA = 2.4 cm and OC = 3.6 then find out (i) AM/BM. (ii). if BO = 3cm , find the value DO
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In a right triangle BAD,
We have OM parallel to side DA of triangle BAD. So triangle BMO is similar to triangle BAD by AA similarity criteria.
Thus corresponding sides of similar triangles are proportional.
Thus, OM÷AD = BM÷AB, which implies, OM÷2.4 = BM÷AB ...........(1)
In the same way, triangle ABC is similar to triangle AMO.
Thus, we have OM÷3.6 = AM÷AB .........(2)
(1)+(2) gives (OM÷2.4)+(OM÷3.6)=(BM÷AB)+(AM÷AB)
On simplifying this,
we get OM = (3.6 × 2.4) ÷ 6 = 1.44 cm
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