Question

if linear momentum increased by 40% then the kinetic energy would increase by

Answer 1

Suppose the original momentum of the body to be ‘p’ and a 40% increase leads to a momentum of p+(40/100)p=1.4p

The relation between momentum ‘p’ and kinetic energy ‘k’ is p²=2km (m is mass of object)

Hence k=(p²)/2m

New kinetic energy(k') is given by,

k' = (1.4p)²/2m ......( as new p is 1.4p)

k'=1.96×((p²)/2m) =1.96×k

now % change in kinetic energy is

((k'-k)/k)×100=((1.96k-k)/k)×100=0.96×100=96%

Hence the required answer is =96%