Question

If linear momentum is increased by 50% then kinetic energy

Answer 1

Answer:Kinetic energy K and linear momentum P are related as

K=P22m………(1)

The new momentum is P+50% 0f P =(3/2)P.

If the new kinetic energy is K’ then

K′=(3/2)P22m=94p22m………(2)

Divide equation (2) by Equation (1) to get

K′=(9/4)K

Now the % change in K is

K′−KK100=(9/4)K−KK100= 125%

Explanation:answer above

Answer 2

Answer:

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