Question

If linear momentum of a body increase by 20%.what will be % increase in kinetic energy of body .solve
by method of dimensions

Answer 1

Increase in linear momentum = p+20%p = 1.2 p

Since p= √2K.E.m

1.2p= √2nK.E.m (where n is the times K.E. increased)

Dividing both the equation we get

1.2 = √n

n = 1.44

Thus the K.E. increases 1.44 K.E

% = 1.44 K.E. - K.E ÷ K.E. ×100 = 44%