If linear momentum of abody is increased by 20 % what will be the % increase in the kinetic energy of the body
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Answer:
Kinetic energy is increased by 44%.
Explanation:
Linear momentum(p) = mv
Kinetic Energy(K) = 1/2 mv² or mv²/2
Linear momentum is increased by 20%.
Linear momentum is directly proportional to velocity, (considering mass of the Body be constant).
So, 20% increase in momentum means 20% increase in Velocity.
Now new velocity, v' = v + 20% of v
v' = ( 1 + 20% ) of v
= (1 + (20/100)) × v
v' = 1.2v ___________(1)
Now, new kinetic energy, K' = mv'²/2
K' = (m (1.2v)²)/2 = (1.44mv²)/2
So, increase in Kinetic energy= K' - K
= 1.44mv²/2 - mv²/2 = 0.44
Percentage increase = [((K'-K)/K)*100]%
= [(0.44/1)*100]%
= 44%
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