Math, asked by mitalikumari7692, 11 months ago

If lines PQ and RS intersect at a point T such that angle PRT= 40° angle RPT=95° angle TSQ=75° find angle SQT

Answers

Answered by Anonymous
8

Answer:

hiii your answer is here !

Step-by-step explanation:

ang. ptr=180-(ang.prt+ ang. rpt)

=180-(40+95)

=180-135

=45

ang.ptr=ang.stq. ( vertically opposite angle)

ang sqt=180-(ang.stq+ang.tsq)

=180-(45+75)

=180-120

=60 (answer)

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Answered by annu183710
6

Answer:

60=sqt

Step-by-step explanation:

180=sum of all angle of triangle

let's ptr=x

180=95+40+x

180=135+x

180-135=x

45=x

ptr=stq(vertically opposite angle)

45=stq

180=angle sum of triangle

180=75+45+sqt

180=120+sqt

180-120=sqt

60=sqt

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