If lines pq and rs intersect at point t such that angle prt =40 and angle rpt =95 and angle tsq =75 find angle sqt
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Given :- angle PRT = 40°, angle RPT = 95°, angle TSQ = 75°
To find :- angle SQT
95° + 40° + angle 1 = 180° (angle sum property).
135° + angle 1 = 180°
angle 1 = 180°
135°
angle 1 = 45°
angle 2= angle 1 (vertically opp. angles)
angle 2 = 45°
75° + angle 2 + angle 3= 180° (angle sum property).
75° + 45° + angle 3= 180°
120° + angle 3 = 180°
angle 3 = 180° - 120°
angle 3 = 60°
Therefore, SQT = 60°
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