If lines PQ and RS intersect at point T, such that ∠PRT = 40°, ∠RPT = 95° and ∠TSQ= 75°, find ∠SQT. In Fig. 6.42.
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IN ΔPRT
∠PRT+∠RTP+∠TPR=180°(∠s SUM PROPERTY)
40°+∠RTP+95°=180°
∠RTP=45°
NOW , ∠RTP=∠QST=45°(VERTICALLY OPPOSITE ∠s)
NOW , IN ΔQST
∠T+∠Q+∠S=180°
45°+∠Q+75°=180°
∠Q=60°
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2
Answer:
Step-by-step explanation:
IN ΔPRT
∠PRT+∠RTP+∠TPR=180°(∠s SUM PROPERTY)
40°+∠RTP+95°=180°
∠RTP=45°
NOW , ∠RTP=∠QST=45°(VERTICALLY OPPOSITE ∠s)
NOW , In ΔQST
∠T+∠Q+∠S=180°
45°+∠Q+75°=180°
∠Q=60°
Hence,∠Q=60°
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