If LM parallel to CB and LN patallel to CD prove that AM/AB = AN/AD.
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Answered by
1
given lm parallel to cb.
ln parallel to cd .
then am/ab= an/ad [theorem 6.1]
Answered by
7
given that LM is parallel to cd and Ln to CD
to prove= am/an = an/ad
proof: in triangle abc lm is parallel to Cb
AL/LC=am/MB (by basic proportionality theorem)-1
in triangle acd
AL/CD=AN/ND (by bpt theorem)-2
from equation 1 and 2
AM/MB=AN/ND
MB/am =ND/AN (reciprocal)
adding 1 on both the sides=mb+am/am=nd+an/an = ab/am=ad/an
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