Math, asked by rajputsr9208, 1 year ago

If log = 0.3010 and log 3= 0.477. Evaluate log6

Answers

Answered by suraj442367
0

x=log5(29)=9log(2)log(5)=9log(2)log(10/2)==9log(2)1−log(2)

=2.7090.699≈3.876

(c) 3.876

Similar questions