Question

If log 0.5 = 1.6990 then the number of zeros that are between the decimal
point and first significant figure in (0.5)¹⁰⁰​

Answer 1

Answer:

Let N=(

6

1

)

200

Taking log both side on base 10.

logN=200log

6

1

=−200log6=−200(log2+log3)=−200(.301+.477)=155.6

Hence, number of required cyphers =155

Answer 2

Answer:

answer is 30

Step-by-step explanation:

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