Question

if log 10 2=0.3010,Log10 3=0.4771 then the number of digits in (2to the power10 and 3 to the power 5) to the power of 20​

Answer 1

Step-by-step explanation:

GIVEN,

$log_{10}(2) = 0.3010$

$log_{10}(3) = 0.4771$

then find,

$( { {2}^{10} \times {3}^{5} })^{20}$

contains how many digits

Apply log;

$= log_{10}( { {2}^{10} \times {3}^{5} })^{20}$

$= log_{10}( { {2}^{200} \times {3}^{100} })$

$= log_{10}( {2}^{200} ) + log_{10}( {3}^{100} )$

$= 200 log_{10}(2) + 100 log_{10}(3)$

$= 200 \times 0.3010 + 100 \times 0.4771$

$= 60.20 + 47.71$

$= 107.91$

THEREFORE, THERE ARE 5 DIGITS.

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Answer 2

bitter butter she did it better so it is bitter butter

Step-by-step explanation:

say this 3 times fast