Question

if
log (10)2=0.30103 and log(10)3=0.47712 then evalute log(10)5 and log(10) 1.2 without using logtable.​

Answer 1

Answer:

log(10) 5=0.69897 & log(10) 1.2=0.07918

Step-by-step explanation:

log(10)5 =log(10)10/2 =log(10)10-log(10)2 =1-0.30103

=0.69897

log(10)1.2 =log(10)12/10 =log(10)12-log(10)10

=log(10)2×2×3 - 1 =log(10)2×2 + log(10)3 -1

=2log(10)2+log(10)3 - 1 = 2×0.30103+0.47712-1

=0.07918