Question

If log 108 - log 176-log x +log 396 -log 81=0, then find the
value of 'x.​

Answer 1

Step-by-step explanation:

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Answer 2

Value of x is 3

Step-by-step explanation:

Given,

log108 - log176 - logx + log396 - log81 = 0

or, logx = log108 - log176 + log396 - log81

or, logx = (log108 + log396) - (log176 + log81)

or, logx = log(108 * 396) - log(176 * 81)

or, logx = log{(108 * 396) / (176 * 81)}

or, logx = log(42768/14256)

or, logx = log3

Then x = 3

Therefore the required solution is

x = 3

Logarithmic rules:

• log(ab) = loga + logb

• log(a/b) = loga - logb

• loga = logb gives a = b

Note:

To solve this type of problems, do remember to take the constantly terms to one side and use the logarithmic formuae for products and divisions.