if log 108 - log 176 - log X + log 396 - log 81 = 0 , then find the value of X
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Value of x is 3
Step-by-step explanation:
Given, log108 - log176 - logx + log396 - log81 = 0
or, logx = log108 - log176 + log396 - log81
or, logx = (log108 + log396) - (log176 + log81)
or, logx = log(108 * 396) - log(176 * 81)
or, logx = log{(108 * 396) / (176 * 81)}
or, logx = log(42768/14256)
or, logx = log3
Then x = 3
Therefore the required solution is x = 3
Logarithmic rules:
• log(ab) = loga + logb
• log(a/b) = loga - logb
• loga = logb gives a = b
Note:
To solve this type of problems, do remember to take the constantly terms to one side and use the logarithmic formuae for products and divisions.
Some other logarithmic problems:
https://brainly.in/question/13218427
https://brainly.in/question/2263417
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