If log 16/81 = x (log 2-log 3) then the
value of 2x-1 =
A) 4
B)8
C)6
D)7
Answers
Answered by
1
Answer:
D)7
Step-by-step explanation:
log2^4/3^4=xlog2-xlog3
=log2^x/3^x
comparing both side we have, x=4
So, 2x-1=7
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