Question

If log 16/81 = x (log 2-log 3) then the
value of 2x-1 =
A) 4
B)8
C)6
D)7​

Answer 1

Answer:

D)7

Step-by-step explanation:

log2^4/3^4=xlog2-xlog3

=log2^x/3^x

comparing both side we have, x=4

So, 2x-1=7