Question

if log 16/ 81 =X( log 2 - log3) then what is the value of 2 X - 1​

Answer 1

Answer:

7.

Step-by-step explanation:

⇒log 16/81=x(log2-log3),

⇒log 16-log 81=x(log2-log3),

⇒log2^4-log3^4=x(log2-log3),

⇒4log2-4log3=x(log2-log3),

⇒4(log2-log3)=x(log2-log3),

⇒x=4,

Then the value of 2x-1 is,

⇒2x-1,

⇒2(4)-1,

⇒8-1,

⇒7.

HOPE IT HELPS.