Question

if log 16/81=x( log2-log3)then find value of 2x-1​

Answer 1

Answer:

7

Step-by-step explanation:

$\bold{log \frac{16}{81} = x(log2 - log3)}$

$\bold{log16 - log81 = x(log2 - log3)}$

$\bold{log {2}^{4} - log {3}^{4} = x(log2 - log3)}$

$\bold{4 \: log2 -4 \: log3= x(log2 - log3)}$

$\bold{4(log2 -log3)= x(log2 - log3)}$

$\bold{ \frac{4(log2 -log3)}{(log2 - log3)}= x}$

$\bold{ 4= x}$

$\bold{ \blue{then \: \: find \: \: value \: \: of \: \: 2x - 1}}$

$\bold{2x - 1 = \pink{2(4) - 1 }= \green{8 - 1 }= \red{7}}$

Answer 2

ur answer is there

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i hope u will understand !!