Question

If log 2=0.301 and log 3=0.4771,find the number of digits in 48^12.​

Answer 1

Answer:

We have log 4812 = 12 × log 48 = 12 × log (24 × 3)

= 12 × (4 log 2 + log 3)

= 12 × (4 × 0.301 + 0.4771)

= 12 × (1.204 + 0.4771)

= 12 × 1.6811 = 20.1732

Now the characteristic is 20, so the number of digits = 20 + 1 = 21.

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