Question

If log 2 = 0.301, what is the number of digits in 4^50?

Answer 1

log2 =0.301-----(1)
let
x=4^50
x=(2^2)^50
x=2^100
take log bothsides
log x=log 2^100
log x=100×log 2
=100×0.301 (from (1))
=30.1
in the expansion of 4^50 number of digits are 31

Answer 2

Hi friend,

log2=0.301
What is the no,of digits in 4^50
Let a=4^50
a=(2²)^50
a=2^100
Take logarithms on both sides,
log a = log 2^100
log a=100 log 2
log a=100(0.301)
=30.1

Therefore,the no.of digits are 31

Hope it helps