Question

if log 2 =0.3010&log 3=0.4771 find the value of log 3.6​

Answer 1

$log \: 3.6 \\ \\ = log \: \frac{36}{10} \\ \\ = log36 - log10 \\ \\ = log {6}^{2} - 1 \\ \\ = 2 \times log(2 \times 3) - 1 \\ \\ = 2( log2 + log3) - 1 \\ \\ = 2 (0.30103 + 0.47712) - 1 \\ \\ = 2 \times 0.77815 - 1 \\ \\ = 1.5563 - 1 \\ \\ = 0.5563$