If log 2 = 0.3010 and log 3 = 0.472. Find the value of the following
(i) log 6 (ii) log 8 (ili) log 12
Answers
Answered by
0
Answer:
answer : option number : iiii
log 12
I think
Answered by
4
Answer:
1) log 6 can be written as log(2*3),
= log 2 + log 3,
= 0.3010 + 0.472,
= 0.773,
2) log 8 can be written as log(2*4),
= log 2 + log 4,
= log 2 + log (2*2),
= log 2 + log 2 + log 2,
= 3 log 2,
= 0.903,
(or)
log 8 can be written as log(2^3),
= 3 log 2,
= 0.903,
3) log 12 can be written as log(4*3),
= log 4 + log 3,
= log (2^2) + log 3,
= 2 log 2 + log 3,
= 0.602 + 0.472,
= 1.074
Used formulae :
log ab = log a + log b,
log (a^b) = b log a.
Hope it helps u...
Similar questions