if log 2 = 0.3010 and log 3 = 0.4771 find value of
log 1.2
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Heya user,
log ( ab / c ) = log a + log b - log c
Also, 1.2 = 3 * 4 / 10
.'. log [ 1.2 ] = log [ 4 * 3 / 10 ]
===== log 4 + log 3 - log 10
===== log 2² + log 3 - log 10
===== 2 ( log 2 ) + 0.4771 - 1
===== 2 ( 0.3010 ) + 0.4771 - 1
===== 0.6020 + 0.4771 - 1 = 1.0791 - 1 = 0.0791
Hence, log 1.2 = 0.0791
log ( ab / c ) = log a + log b - log c
Also, 1.2 = 3 * 4 / 10
.'. log [ 1.2 ] = log [ 4 * 3 / 10 ]
===== log 4 + log 3 - log 10
===== log 2² + log 3 - log 10
===== 2 ( log 2 ) + 0.4771 - 1
===== 2 ( 0.3010 ) + 0.4771 - 1
===== 0.6020 + 0.4771 - 1 = 1.0791 - 1 = 0.0791
Hence, log 1.2 = 0.0791
Anonymous:
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