If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512
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given
log 2 = 0.3010 ----(1)
log 3 = 0.4771 ---(2)
write 512 as product of prime factors
512 = 2*2*2*2*2*2*2*2*2 = 2^9
log 512 = log 2^9=9 log 2
= 9*(0.3010) from (1)
= 2.709
log 2 = 0.3010 ----(1)
log 3 = 0.4771 ---(2)
write 512 as product of prime factors
512 = 2*2*2*2*2*2*2*2*2 = 2^9
log 512 = log 2^9=9 log 2
= 9*(0.3010) from (1)
= 2.709
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