Question

If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512

Answer 1

given 
log 2 = 0.3010 ----(1)
log 3 = 0.4771 ---(2)
write 512 as product of prime factors
512 = 2*2*2*2*2*2*2*2*2 = 2^9
log 512 = log 2^9=9 log 2

= 9*(0.3010) from (1)
= 2.709