If log 2= 0.3010 ,log 3 = 0.4771, log 5 =0.6990
Then find the value of log 120
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log(120)=log(2×2×2×3×5)
we know log(abc)=log a+ log b + log c
log(120)=log(2)^3+log 3 +log 5
log(120)=3log 2 + log 3 +log 5
log(120)=3(0.3010)+(0.4771)+(0.6990)
log(120)=0.903+0.477+0.6990
log(120)=2.079
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