if log 2 = 0.3010,log 3=4771,log 5 = 0.6990, then find the value of log 16 over 15
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Answer:
Given values
log2 = 0.3010
log 3 = 0.4771
To find the value of log 25.
Log 25 can be expressed as
log 25 = log (5 × 5)
log 25 = log 5 + log 5
log 25 = log(10/2) + log(10/2)
log 25 = (log 10 – log 2) + (log 10 – log 2)
log 25 = (1 – 0.3010) + (1 – 0.3010)
log 25 = 0.6990 + 0.6990
log 25 = 1.3980
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